1+(4/x^2)=0

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Solution for 1+(4/x^2)=0 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4/(x^2)+1 = 0

4*x^-2 = -1 // : 4

x^-2 = -1/4

-2 < 0

1/(x^2) = -1/4 // * x^2

1 = -1/4*x^2 // : -1/4

-4 = x^2

x belongs to the empty set

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